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4x^2-2x=650
We move all terms to the left:
4x^2-2x-(650)=0
a = 4; b = -2; c = -650;
Δ = b2-4ac
Δ = -22-4·4·(-650)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10404}=102$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-102}{2*4}=\frac{-100}{8} =-12+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+102}{2*4}=\frac{104}{8} =13 $
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